plz help me...and solve this ...write the steps of construction
Answers
Step-by-step explanation:
Constructing a 60° angle
To construct a 60° angle, we first draw a line of any length. Then using a compass, we use this as a base to construct an equilateral triangle.
To construct the equilateral triangle, we:
1.open the compass to the same dimensions as our original line
2.place the point of the compass on one end of the line and draw an arc
3.repeat this at the other end and the arcs should intersect where the tip of the triangle should be Connect the tip of the triangle to one end of the base, and you will have a 60° angle.
Constructing a 22.5 degree angle
Step 1: A ray from OB is drawn.
Step 2: Draw a perpendicular bisector to the line A
′
B.Join AO and AB
Step 3: Draw a perpendicular bisector to the line AB then ∠BOD=45 ∘
∴∠BOD=45 ∘
Step 4: Draw a perpendicular bisector to the line BD
∴∠BOC=22.5 ∘
Thus,∠BOC is the required angle making 22.5∘
Constructing a 75 degree angle
Step 1: Draw a line segment with endpoint O and A.
Step 2: Draw an arc with O as centre cutting the line segment OA at point B with a compass.
Step 3: Keeping the radius same, Draw an arc with B as centre cutting the arc at C.
Step 4: Keeping the radius same, and C as the center, draw an arc intersecting the arc drawn in the previous step at D.
Step 5: With any radius, Draw two arcs with C and D as a center. Intersect these two arcs at E.
Step 6: Join OE. angle EOA is the angle with measurement of 90 degrees.
Step 7: Now the line OE intersect the arc at the point F.
Step 8: Taking F and C as a center, make an arc with a radius of more than half of the measurement FC. The arc intersects at point H.
Step 9: Join the point H and O. Angle HOA is the angle obtained of measurement 75 degrees.
Step 10: Angle HOA is the desired angle.
Constructing a 105 degree angle
The angle of measurement 105 0 can be constructed as per the steps given below
1: Draw a ray AB.
2: Considering A as the centre and width of any radius, draw an arc cutting AB at C.
3: Considering C as the centre and the same radius, draw an arc cutting the first arc at D.
4: Considering D as the centre and the same radius, draw another arc cutting again the first arc at G.
5: Considering D and G as centres and with the same radius, we draw two arcs cutting each other at F.
6: Join AF which makes 90°.
7. Mark the point where the semicircular arc cuts the line AF as E.
8: Considering G and E as centres and with the same radius draw two arcs cutting each other at H.
9. Now join the points A and H.
∠HAB = 105°.
Constructing a 135 degree angle
(a) Draw a line PQ and take a point O on it.
(b) Taking O as the centre and convenient radius, mark an arc, which intersects PQ at A and B.
(c) Taking A and B as centres and radius more than half of AB, draw two arcs intersecting each other at R.
(d) Join OR. Thus, ∠QOR = ∠POQ = 90 .
(e) Draw OD the bisector of ∠POR. Thus, ∠QOD is the required angle of 135
please mark me as Brainliest answer!!!!!!!