Math, asked by ria32, 1 year ago

plz..help me friends

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Answered by TheAishtonsageAlvie

Hey there!!

In fig ,
in ∆ABD and ∆BCD

AB = CD (Given)

Ang ABD = AngCDB ( each of 90°)

BD = BD ( common)
Hence
∆ ABD. ~= ∆BCD ( SAS)
nd hence
AD = BC ( CPCT )

Hope this helps u
^_^

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