Math, asked by rehannadeem2007, 1 year ago

plz help me guys urgent

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Answered by Debanshii
0
AB is parallel to CD ,
Thus , when AD is the transversal
Angle A = Angle D
when BC is the transversal
Angle B = Angle C
so in triangle AOB and traingle DOC
angle A = Angle D
Angle B = angle C
angle AOB = angle DOC
thus traingle AOB is congruent to triangle DOC
therefore, OA=OD (CPCT)
OB= OC (CPCT)

Hence, proved.
Answered by dvipada07
2

Answer:

3. yes

4.yes

Step-by-step explanation:

3. given that,AD=BC,AB=CD

ΔABD                                     ΔCDB               Reason

AD                        =                  BC                  given

AB                        =                  CD                   given

BD                         =                 DB                    common side

∴≅ΔCDB under the SSS congruence criterion

4.given that OA=OD,OB=OC

ΔAOB                                   ΔDOC                         REASON

OA                      =                 OD                             given

OB                      =                  OC                            given

∠AOB                 =                  ∠COD                       vertically opposite angles(AB║ CD)

∴ΔAOB ≅ΔDOC under the SAS congruence criterion

hope it helps

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