Question

plz help me I m not getting this

Answer 1

hey friend here is the solution to this question

in triangle aob
OA =OB(radii of the circle )
so angle oba =angle bao=x°(let) (angles opposite to equal sides requL )
angle BAO +ANGLE AOB+ANGLE OBA=180° [angle sum property of the triangle ]
so
x°+x°+80°=180°
2x=100°
x=50° =angle oab
similarly we get angle OAC = 35°
angle BAC= angle oab+oac=35°+50°=85°

Answer 2

angle BAC = 90° [ it is half-circled angle ]
so, the ans is 90°