Question

plz help me. i need the answer pronto! plzzz

Answer 1

Answer:

Given:

Car of mass 500 kg moves up the hill at constant speed

To find:

Work done in moving the car up the hill

Assumptions:

Friction is neglected.

Concept:

Gravitational force is a conservative force. So whenever work is done in association with this force, we shall only consider the perpendicular distance from tge reference point.

The work done by the car is actually stored as the potential energy at the top of the hill.

Calculation:

Work done = Potential Energy

$= > work = m \times g \times \: h$

$= > work = 500 \times 10 \times 10$

$= > work = 5 \times {10}^{4} joules$

So final answer is :

$\boxed{ \red{ work \: done \: is \: 5 \times {10}^{4} joules}}$

Answer 2

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$\huge\red\bigstar$ GIVEN:

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•M=500kg.

•g=10N/kg.

•h=10m

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$\huge\red\bigstar$ FIND:

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•work done by car.

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$\huge\red\bigstar$CONCEPT:

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The principle of work and potential energy also known as the work-energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the potential energy of the particle. ... The potential energy of the block increases as a result by the amount of work.

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$\implies$.°. WORK=POTENTIAL E.

$\implies$WORK=MGH

$\implies$ WORK=500×10×10

$\implies$. .°. WORK=5×10^4J.

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$\huge\red\bigstar$ HENCE.

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$\huge\red\bigstar$ option. $\red{B}$ is the right answer

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$\huge\red\bigstar$ WORK DONE BY CAR IS 5×10^4 J.

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