plz help me in this....
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BE and AD are perpendiculars to l
So BE|| AD
Join BD and let it intersect CM at X
In Tiangle ABD
C is the mid point of AB and CX ||AD
so by converse of M. P. T
X is the midpoint of BD
Similarly in Triangle BDE
M will be proven the midpoint of DE
In triangle CME And triangle CMD
Angle CME = ANGLE CMD =90
CM = CM
DM = EM (PROVED)
SO TRIANGLE CME CONGRUENT TO TRIANGLE CMD BY S. A. S
AND CD = CE BY C. P. C. T.
So BE|| AD
Join BD and let it intersect CM at X
In Tiangle ABD
C is the mid point of AB and CX ||AD
so by converse of M. P. T
X is the midpoint of BD
Similarly in Triangle BDE
M will be proven the midpoint of DE
In triangle CME And triangle CMD
Angle CME = ANGLE CMD =90
CM = CM
DM = EM (PROVED)
SO TRIANGLE CME CONGRUENT TO TRIANGLE CMD BY S. A. S
AND CD = CE BY C. P. C. T.
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