Question

plz help me in this maths problem​

Answer 1

Answer:

in 6th question

Step-by-step explanation:

x=$\sqrt{2}$+1

so 1/x=1/($\sqrt{2}$+1)

now

$(x+1/x)^{2}$=$x^{2}$+1/$x^{2}$+2

now put value of x and 1/x

{($\sqrt{2}$+1)+1/($\sqrt{2}$+1)}whole square=$x^{2}$+1/$x^{2}$+2

{2+1+2$\sqrt{2}$}/$\sqrt{2}$+1}whole square -2 =$x^{2}$+1/$x^{2}$

{$(3+2root2)^{2}$/3+2root2}-2=$x^{2}$+1/$x^{2}$

3+2root2-2

1+2$\sqrt{2}$=$x^{2}$+1/$x^{2}$

similarly you can solve by using identity

(a+b)whole cube idientiy equate and you will get it

please forgive me for not solving 7 question

if you understood and was able to solve 7 question

then please mark brainleist