plz help me in this maths question of geometry ( similarity) hope you will help me to complete this homework and I will mark you as brainliest
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For this, we need to recall a property that if a line is drawn parallel to a side of a traingle, it divides the remaining two sides in the same ratio.
Now in triangle BAE, DF||AE
hence, BF/FE= DE/EA (using above property)-----eqn 1
Again in triangle BAC, DE|| AC
hence BE/EC= DE/EA------- eqn 2
from eqn 1 and 2, we have
BF/FE=BE/EC..proved
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