Question

plz help me in this question

Answer 1

answer is 3^5refer the pic
hope it'll help
mark it as brainliest..

Answer 2

Hey friend,
Here is the answer you were looking for:
$\frac{ {3}^{n} \times {9}^{n + 1} }{ {3}^{n - 1} \times {9}^{n - 1} } \\ \\ = \frac{ {3}^{n} \times ({3}^{2} ) ^{n + 1} }{ {3}^{n - 1} \times ({3}^{2})^{n - 1} } \\ \\ = \frac{ {3}^{n} \times {3}^{2 \times n + 2 \times 1} }{ {3}^{n - 1} \times {3}^{2 \times n - 2 \times 1} } \\ \\ = \frac{ {3}^{n} \times {3}^{2n + 2} }{ {3}^{n - 1} \times {3}^{2n - 2} } \\ \\ using \: the \: identity \\ {a}^{m} \times {a}^{n} = {a}^{m + n} \\ \\ = \frac{ {3}^{n + 2n + 2} }{ {3}^{n - 1 + 2n - 2} } \\ \\ = \frac{ {3}^{3n + 2} }{ {3}^{3n - 3} } \\ \\ using \: the \: identity \\ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} \\ \\ = {3}^{(3n + 2) - (3n - 3)} \\ \\ = {3}^{3n + 2 - 3n + 3} \\ \\ = {3}^{2 + 3} \\ \\ = {3}^{5} \\ \\ = 243$

Hope this helps!!!

@Mahak24

Thanks...
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