plz help me in this question
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7.
10 ^2 = 3x^2 + 4x^2
100 = 3*2)^2 + 4*2)^2
100 = 6^2 + 8^2
100 = 36 +64
so other two sides = 6 cm and 8 cm
8'. diagonal= x
x^2 =12^2+ 5^2
x^2 = 144 +25
x^2 = 169
x = 13 cm
9. length if the other side = x
20^2 = 16^2 + x^2
400 =256 + x^2
400-256 = x^2
144 = x^2
x = 12 cm
so perimeter = 12+20+ 16+ cm
48 cm
I'll answer for other two in the morning
10 ^2 = 3x^2 + 4x^2
100 = 3*2)^2 + 4*2)^2
100 = 6^2 + 8^2
100 = 36 +64
so other two sides = 6 cm and 8 cm
8'. diagonal= x
x^2 =12^2+ 5^2
x^2 = 144 +25
x^2 = 169
x = 13 cm
9. length if the other side = x
20^2 = 16^2 + x^2
400 =256 + x^2
400-256 = x^2
144 = x^2
x = 12 cm
so perimeter = 12+20+ 16+ cm
48 cm
I'll answer for other two in the morning
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