Question

plz help me it is important​

Answer 1

Answer:

∠ACO=30°

Step-by-step explanation:

In the given figure;

   ∠AOB + ∠AOC = 180°  [Linear pair of angles]

   ∠AOB = 60° [Given]

   60° + ∠AOC = 180°

   ∠AOC = 180° - 60° = 120°

         ∴ ∠AOC=120°.

In ΔAOC;

   AO = OC [Radii of the same circle]

   Therefore, ΔAOC is a isosceles triangle.

   ∠AOC+∠OAC+∠ACO = 180° [Angle Sum Property]

   120°+2∠ACO = 180°

   2∠ACO = 180° - 120° = 60°

  ∠ACO = $\frac{60}{2}$ ° = 30°