Question

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please tell all questions and by solving

Answer 1

Answer:

hey there can u please send it correctly because its not clear

Answer 2

Answer:

1)=Here, Radius of Curvature of the mirror is 30cm

2)=Here, The object is about 60cm in front of the mirror and is real and inverted. Size of the Image is 8cm.

Explanation:

1)=Here, As per our given question,

=Focal length(f) of the mirror =15cm

=Radius of Curvature(R) of the mirror=?

Now, As it is considered that,

=f=R/2

=So, R=2f

=R=15×2

=R=30cm

Hence, The value of R in this Convex mirror =30cm.

2)=Here, As given in question,

=Height of the object(ho)=4cm

=Focal length(f) of the mirror=(-20cm) (As value of f in Concave mirror is in negative)

=Distance of object from the mirror(U)=(-30)cm

=Distance of image from the mirror(V)=?

Now, As it is considered that,

=1/f=1/V+1/U

=1/(-20)=1/V+1/(-30)

=1/V=1/(-20)+1/30

After taking Lcm and solving it, we get,

=1/V=[(-3)+2]/60

=1/V=(-1)/60

Now, by doing reciprocal on both sides, we get,

=V=(-60)

=V=60cm

Now, Magnification(M)= M=(-V)/U

=M=60/-30

=M=2/(-1)

=M=(-2)

Here, The position of image is 60cm in front of the mirror and is real and inverted.

Now, height of image(hi)= M=hi/ho

=hi=M×ho

=hi=2×(-4)

=hi=(-8)

=hi=8cm

Thank you.