plz help me out to find this
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I have write only 7).
there are your answer
2.3^x =0.23^y =1000
consider 2.3^x =1000
log 2.3 ^x = log 10^3
x log 2.3 = 3 log 10
log 2.3 =3/x [: log 10 =1] ....l
consider 0.23 ^y =1000
log 0.23 ^y= log 1000
y log 0.23 =log 10^3
y log 0.23 =3log 10
log 0.23 =3/y .....ll
subtract eq.ll from l
log 2.3 - log0.23=3/x - 3/y
log 2.3/ 0.23 = 3/x - 3/y
log 10 =3/x - 3 / y
1= 3/x - 3/y
3( 1/x - 1/y) =1
1/x - 1/y =1/3
thank you
plzzzz mark brainiest
there are your answer
2.3^x =0.23^y =1000
consider 2.3^x =1000
log 2.3 ^x = log 10^3
x log 2.3 = 3 log 10
log 2.3 =3/x [: log 10 =1] ....l
consider 0.23 ^y =1000
log 0.23 ^y= log 1000
y log 0.23 =log 10^3
y log 0.23 =3log 10
log 0.23 =3/y .....ll
subtract eq.ll from l
log 2.3 - log0.23=3/x - 3/y
log 2.3/ 0.23 = 3/x - 3/y
log 10 =3/x - 3 / y
1= 3/x - 3/y
3( 1/x - 1/y) =1
1/x - 1/y =1/3
thank you
plzzzz mark brainiest
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