plz help me plz help me
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Answer:
Iodine being an oxidizing agent oxidises ethanol to ethanal
And as ethanal contains (CH3CO)-group
It gives iodoform test
That is yellow ppt of CHI3 are formed
The base NaOH abstract acidic protons(alpha to carbonyl group) of ethanal resulting in enolate ion that attacks on I2 molecules
At last cleavage occurs.
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0
Answer:
iodoform + sodium formate
Explanation:
since ethyl alcohol is having CH-OH group , it answers iodoform test...
hence , product will be CHI3 and HCOONa
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