Question

plz help me plz plz now​

Answer 1

Answer:

h=18cm

Step-by-step explanation:

given,

PQR=triangle and ABCD= parellogram

same area and have same base

SIDES= 28,26 and 30cm

area = $\sqrt{s(s-a)(s-b)(s-c)}$

s=$\frac{a+b+c}{2}$

s= 28+26+30/2

= 84/2

= 42

so s=42

$=\sqrt{42(42-30)(42-28)(42-26}\\=\sqrt{42(12)(14)(16)} \\=\sqrt{6*7*6*2*7*2*4*4} \\=6*7*2*4\\= 42*12\\=504cm^2$

so the area of the triangle is 504cm^2

as the area of parlleogram would be equal to triangle

so the area of parallelogramis 504cm^2

area of parellogram = base * height

504=28*h

504=28h

$\frac{504}{28}=h$

h= 18

so the height of the parallelogram is 18cm

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