Question

plz help me solve it

Answer 1

quadric eq is..

3x2-2x=1
because the value of alpha and beta from given eq is 2
then 1/2+1/2=1 so x=1
hope it helps u..

Answer 2

$\alpha \: \: \beta \: are \: roots \: of \: 6 {y}^{2} - 7y + 2$
we have to form the equation whose roots are
$\frac{1}{ \alpha } \frac{1}{ \beta }$
take
$y = \frac{1}{ \alpha } > > > \alpha = \frac{1}{y}$
now
$6 { \alpha }^{2} - 7 \alpha + 2 = 0$
put
$\alpha = \frac{1}{y}$
we get
$2 {y}^{2} - 7y + 6 = 0$
this is the required equation