Question

plz help me to solve it no. 3​

Answer 1

Hey mate Here is ur answer .

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Answer 2

$\bold{We \: can \: convey \: from \: question}$

$\mathsf{AO = OB}$

$\mathsf{OC = OD}$

(i)For ΔAOC and ΔBOD

$\mathsf{AO = OB \: (Given)}$

$\mathsf{OC = OD \: (Given) }$

$\mathsf{\angle AOC = \angle DOB \: (vertically \: opposite \: angle) }$

Therefore,

ΔAOC $\cong$ ΔDOB

(ii) AC = BD

Since,

ΔAOC $\cong$ ΔDOB

So, by C. P. C. T. C

AC = BD.

(iii) AC||BD

Since,

ΔAOC $\cong$ ΔDOB

So, the angles of triangles are also equal which means,

$\mathsf{\angle OAC = \angle DBO}$

$\mathsf{\angle OCA = \angle ODB}$

Since, these angles are alternate interior hence we can say

AC is parallel to BD.