plz help me to solve its 2 part sum no. 1
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Done...........................
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Randhawamuskan:
you r great
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ok ☺
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Any quadratic polynomial can be formed by using the formula :
x^2 - ( sum of zeroes )x + ( product of zeroes)
so as per your question.
x^2 - ( 1/4 - 1)x + ( 1/4 × -1)
x^2 - ( -3/4)x + (-1/4)
x^2 +3/4x - 1/4
L.C.M = 4
So here's your polynomial :
4x^2 + 3x - 1
Hope it helps.
x^2 - ( sum of zeroes )x + ( product of zeroes)
so as per your question.
x^2 - ( 1/4 - 1)x + ( 1/4 × -1)
x^2 - ( -3/4)x + (-1/4)
x^2 +3/4x - 1/4
L.C.M = 4
So here's your polynomial :
4x^2 + 3x - 1
Hope it helps.
of course
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