Plz help me to
solve question no. 18
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Mansi1628:
There is no 18
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Answered by
0
use distance formula
solve for y
you must get a quadratic equation
solve and add up the roots
solve for y
you must get a quadratic equation
solve and add up the roots
Answered by
0
Abscissa means x-co ordinate.
Now according to distance formula,
(10)^2= (10-2)^2 + (x-(-3))^2
100=64+(x-(-3))^2
36=(x-(-3))^2
6=(x+3)
x=3
OR
(10)^2= (2-10)^2 + (-3-x)^2
100-64=(-3-x)^2
36=(-3-x)^2
6=(-3-x)
6+3=(-x)
x=(-9)
so total sum of possible values
=(-9)+3
=(-6).
_-_-_-_-Thanks_-_-_-_
Now according to distance formula,
(10)^2= (10-2)^2 + (x-(-3))^2
100=64+(x-(-3))^2
36=(x-(-3))^2
6=(x+3)
x=3
OR
(10)^2= (2-10)^2 + (-3-x)^2
100-64=(-3-x)^2
36=(-3-x)^2
6=(-3-x)
6+3=(-x)
x=(-9)
so total sum of possible values
=(-9)+3
=(-6).
_-_-_-_-Thanks_-_-_-_
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