plz help me to solve this
Attachments:

Answers
Answered by
0
I hope this is the correct answer
Attachments:

Answered by
1
Here is the solution






![= \frac{1}{2}[ \frac{ \sqrt{3} }{ \sqrt{2} + \sqrt{6} }] = \frac{1}{2}[ \frac{ \sqrt{3} }{ \sqrt{2} + \sqrt{6} }]](https://tex.z-dn.net/?f=%3D++%5Cfrac%7B1%7D%7B2%7D%5B+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B+%5Csqrt%7B2%7D+%2B+%5Csqrt%7B6%7D+%7D%5D)
![= \frac{1}{2}[ \frac{ \sqrt{3} }{ \sqrt{2} + \sqrt{6} }* \frac{\sqrt{2} - \sqrt{6}}{\sqrt{2} - \sqrt{6}} ] = \frac{1}{2}[ \frac{ \sqrt{3} }{ \sqrt{2} + \sqrt{6} }* \frac{\sqrt{2} - \sqrt{6}}{\sqrt{2} - \sqrt{6}} ]](https://tex.z-dn.net/?f=%3D++%5Cfrac%7B1%7D%7B2%7D%5B+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B+%5Csqrt%7B2%7D+%2B+%5Csqrt%7B6%7D+%7D%2A+%5Cfrac%7B%5Csqrt%7B2%7D+-+%5Csqrt%7B6%7D%7D%7B%5Csqrt%7B2%7D+-+%5Csqrt%7B6%7D%7D+%5D)
![= \frac{1}{2}[ \frac{ \sqrt{6}-3 \sqrt{2} }{ 2-6 } ] = \frac{1}{2}[ \frac{ \sqrt{6}-3 \sqrt{2} }{ 2-6 } ]](https://tex.z-dn.net/?f=%3D++%5Cfrac%7B1%7D%7B2%7D%5B+%5Cfrac%7B+%5Csqrt%7B6%7D-3+%5Csqrt%7B2%7D++%7D%7B+2-6+%7D+%5D)

Similar questions