Question

plz help me to solve this also​

Answer 1

Step-by-step explanation:

this is formula of (a+b+c)

$(a + b + c) {}^{2} = a { }^{2} + b {}^{2} + c {}^{2} + 2ab + 2bc + 2ca$

your your answer will be x +2 y + z whole bracket square divide x + 2 y + z=x + 2 y + z.

Answer 2

Step-by-step explanation:

Apply identity of (a+b+c)² = a² + b² + c² + 2(ab + bc + ca)

(-x)² + (2y)² + z² - 4xy - 2xz + 4yz

= (- x + 2y + z)²

= - (x - 2y - z)²

Now dividing it, we get,

= -(x - 2y - z)

= - x + 2y + z

Next Question follows the same pattern.

(√2x)² + (√5y)² + (-z)² + 2√10xy - 2√5yz - 2√2xz

= (√2x + √5y - z)²

= -(- √2x - √5y + z)²

Now the dividend is,

2z - √20y - √8x

= 2z - 2√5y - 2√2x

= 2(z - √5y - √2x)

Now on dividing you get,

-( - √2x - √5y + z) /2

= (√2x + √5y - z) / 2

Here are your answers, Hope it helped. Say thanks, follow me and Mark me brainliest.