Question

plz help me to solve this question....plz plz plz

Answer 1

HEY FRIEND, HERE IS YOUR ANSWER
ANSWER IS 2
$\frac{{2}^{3x - 1} + 10}{7} = 6 \\ = > {2}^{3x - 1} + 10 = 7 \times 6 = 42 \\ = > {2}^{3x - 1} = 42 - 10 \\ = > {2}^{3x - 1} = 32 = {2}^{5} \\ as \: \ {x}^{y - z} = \frac{ {x}^{y} }{ {x}^{z} } \\ so \: {2}^{3x - 1} = \frac{ {2}^{3x} }{2} \\ = > {2}^{3x} = {2}^{6} \\ as \: bases \: are \: equal \: then \: powers \: are \: also \: equal \: so \\ 3x = 6 \\ = > x = 2 \\ value \: of \: x = 2$
I HOPE IT HELPS...!!!