Question

plz help me to solve this question plzzz....​

Answer 1

Answer:

Let the side be a.

$area \: of \: equilateral \: triangle \: = \frac{ \sqrt{3} }{4} {a}^{2} \\ = > 16 \sqrt{3} = \frac{ \sqrt{3} }{4} {a}^{2} \\ = > {a}^{2} = 16 \times 4 = 64 \\ = > a = \sqrt{64} = 8$

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Answer 2

Step-by-step explanation:

Refer to the attachment dear.........