plz help me to spov this trigonometry question
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sin theta = opposite /hypotenuse=12/13
adjacent=5
sin^2 theta - cos^2 theta = (144-25)/169=119/169
2 sin theta cos theta =2*12/13*5/13=120/169
1/tan^2 theta = cos^2 theta/sin^2 theta=25/144
119*169/169*120*25/144
(119/120)*(25/144)
=595/3456
adjacent=5
sin^2 theta - cos^2 theta = (144-25)/169=119/169
2 sin theta cos theta =2*12/13*5/13=120/169
1/tan^2 theta = cos^2 theta/sin^2 theta=25/144
119*169/169*120*25/144
(119/120)*(25/144)
=595/3456
Answered by
1
given,
sinx=12/13=opp.side/hypotenuse
by Pythagoras theroem,
13²=12²+adj.side²
=>13²-12²=adj.side² =169-144=25
=>5²=adj.side²
=>5=adj.side
cosx=5/13
sin²x-cos²x/2sinxcosx * 1/tan²x
=(12/13)²-(5/13)²/2*12/13*5/13 * 1/(12/5)²
=144/169-25/169/2*12*5/169 * 1/144/25
=144-25/169/120/169 * 25/144
=119/120*25/144
=119×25/120×144
=119×5/24×144
=595/3456.
HOPE THE ANSWER IS CORRECT
if it is correct pls mark it as brainliest
sinx=12/13=opp.side/hypotenuse
by Pythagoras theroem,
13²=12²+adj.side²
=>13²-12²=adj.side² =169-144=25
=>5²=adj.side²
=>5=adj.side
cosx=5/13
sin²x-cos²x/2sinxcosx * 1/tan²x
=(12/13)²-(5/13)²/2*12/13*5/13 * 1/(12/5)²
=144/169-25/169/2*12*5/169 * 1/144/25
=144-25/169/120/169 * 25/144
=119/120*25/144
=119×25/120×144
=119×5/24×144
=595/3456.
HOPE THE ANSWER IS CORRECT
if it is correct pls mark it as brainliest
nikki1231:
pls mark it as brainliest
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