Question

Plz help me with these questions (54..n..55)
I'd be truly grateful to u!​

Answer 1

Answer of question number 54

Answer 2

Answer:

55th question Answer as below:

179 : 321

Step-by-step explanation:

Let us assume that for the first AP, the first term is a and common difference is d

For the second AP, the first term is A and the common difference is D,

We need to find 18th term of AP for these series.

=> a + 17d / A + 17D

Now as per the problem,

n/2[2a + (n-1)d] / n/2[2A + (n-1)D]  = 5n + 4/9n + 6

=> 2a + (n-1)d / 2A + (n-1)D =  5n + 4/9n + 6

=> a + (n-1/2)d / A + (n-1/2)D = 5n + 4/9n + 6.

We have to find a + 17d / A + 17d

=> [n - 1]/2 = 17

=> n = 35.

Putting n = 35,

a + 17d/A + 17D = 5 (35) + 4 / 9(35) + 6 = 179 / 321

Therefore 18th term of 1st AP/18th term of 2nd AP = 179/321.