Question

plz help.......plzzzzz​

Answer 1

Answer:

answer of (vi) one

I = ∫[cosecx(cosecx + cotx )].dx

I = ∫(x + cosecx . cotx).dx

I = ∫x .dx + ∫cosecx.cotx.dx

Using indentities:

∫cosec^2 x.dx= -cotx

∫cosecx.cotx.dx = -cosecx

I = -cotx - cosecx + C

Where C is Arbitrary Constant.

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