plz help with this question
a relation R on set {0,1,2,.....,10} defined by 2x+3y=12. find relation,domain and range
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ANSWER:
R = {(0, 4), (3, 2), (6, 0)}
Step-by-step explanation:
A relation R on the set {0, 1, 2,…, 10} defined by 2x + 3y = 12.
Given,
(x, y) R 2x + 3y = 12
Where x and y = {0, 1, 2,…, 10}
2x + 3y = 12
2x = 12 – 3y
x = (12-3y)/2
When, y = 0, x = (12-3(0))/2 = 12/2 = 6
When, y = 2, x = (12-3(2))/2 = (12-6)/2 = 6/2 = 3
When, y = 4, x = (12-3(4))/2 = (12-12)/2 = 0/2 = 0
∴ R = {(0, 4), (3, 2), (6, 0)}
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