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Step-by-step explanation:
Verification:
Substitute each of the values 3, -2, 1 in the given function:
f(x)=x^3 - 2x^2 - 5x + 6
f(3) = 27 - 2(9) - 5(3) + 6 = 27 - 18 - 15 + 6 = 0
Similarly,
f(-2) = f(1) = 0
Sum of zeros:
α + β + γ= - b / a
we have the values of zeros as ( 3, -2 , 1)
taking α=3 , β = -2 and γ = 1
α + β + γ = 3 - 2 + 1 = 2 ----------------- ( 1 )
coefficients: a = 1 , b = -2 , c = -5
- b / a = -(-2) / 1 = 2 ------------------( 2 )
From ( 1 ) and ( 2 ),
α + β + γ = - b / a
Product of zeros:
αβγ = - d / a
αβγ = 3 x (-2) x 1 = -6 -----------( 3 )
- d / a = - 6 / 1 = -6 --------------( 4 )
From ( 3 ) and ( 4 ),
αβγ = - d / a
Hence, verified.
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