Question

plz in need of answers​

Answer 1

✰ Given :-

In triangle ABC, ∠A = 50°, ∠C = 30°

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✰ To Find :-

What is ∠B

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✰ Used Formula :-

$\red{⟹ \: \boxed{ \bf Sum \: of \: all \: angles = 180°}}$

$\:$

✰ Solution :-

In triangle,

Sum of all angles = 180°

Here,

$\red⇝ \bf \angle a = 50 \degree$

$\red⇝ \bf \angle c = 30 \degree$

$\red⇝ \bf \angle b = \: ?$

$\color{navy}{{ \bf⟹ \: ∠a +∠b +∠c = 180°}}$

$\color{navy}{{ \bf⟹ \: 50° +x +30° = 180°}}$

$\color{navy}{{ \bf⟹ \: 80° +x = 180°}}$

$\color{navy}{{ \bf⟹ \: x = 180° - 80°}}$

$\color{navy}{ ⟹ \: \underline{\boxed{ \bf \: x = 100° }}}$

∵ ∠B = 100°

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✰ Verification :-

$\color{orange}{⟹ \: \bf Sum \: of \: all \: angles = 180°}$

$\color{orange}{{ \bf⟹ \: 50° +100 +30° = 180°}}$

$\color{orange}{{ \bf⟹ \: 180° = 180°}}$

∴ Hence, proved !