plz make it fast with step by step explanation I confused with this 5 sums
Answers
Step-by-step explanation:
q 6
A'=(2,4,6,8,10]
complement of set are things which are not included in originated set but included in universal
set U.
Q7
GIVEN:
If n (A) = 20, n (B) = 28 and n(AUB) = 36 then n(AB)
TO FIND :
The value of n(ANB)
SOLUTION :
Given that n (A) = 20, n (B) = 28 and n(AUB) = 36
The formula in Set theory is given by:
n(AUB) = n(A) + n(B)-n(ANB)
Now substituting the values in the above formula we get.
36 = 20+28 n(AB)
36 48 n(An B)
n(AB) 48-36
= 12
n(AB) = 12
the value of n(AB) is 12
Q8
Given: n(AB) =18, n(AUB) =70, n(An B) =25
n(AUB) = n(AB) + n(AB) + n(B - A)
70 18 + 25 + n(B - A)
7043 + n(BA)
n(BA) = 70-43
n(B-A) = 27
Now n(B) = n(AB) + n(B - A)
n(B) = 25+27
n(B) = 52
Q9
Given : 35 Student in art class and 57 in Dance Class 12 students are enrolled in both activities
To find the number of students who are either in dance class or art class
Solution:
Number of Students in Art Class n(A) = 35
Number of Students in Dance class n(D) = 57
Number of Students in Art & Dance class Both n(AND) = 12
number of students who are either in dance class or art class = n(AUD)
n(AUD) = n(A) + n(D) - n(AND)
=> n(AUD) = 35+57-12
=> n(AUD) = 92-12
> n(AUD) = 80
80 number of students who are either in dance class or art class
Q10
Given
a=(2, 3, 4, 5] and b={1, 2, 3, 4, 5, 6]
Then
a Ub = [ everything in one or the other ]
= [1, 2, 3, 4, 5, 6]
(a Ub)' = [ the complement, so everything in u that's not in aUb]
= ( 7, 8, 9, 10).
Also
a' = {1, 6, 7, 8, 9, 10) and b'=[ 7, 8, 9, 10 ]
SO
a' n b' = [those elements in both a' and b']
= [ 7, 8, 9, 10 ].
(a Ub)' = a' nb.
hope it helps you friend
have a nice day