plz me right answer fast plz
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given :triangle ABC
to prove :angle B = angleC
construction :draw a median from A on BC
such that
BD =DC
in triangle ABD and ACD
BD =DC (cons)
AB=AC (given)
AD =AD (common)
by sss congruency rule
ABD ≈ ACD
by cpct..
<B= <C
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