Question

plz plz answer fast​

Answer 1

Plot these points on the Cartesian plain and it would be proved that it is a triangle and hence find its sides....

For finding sides use distance formula

$distance \: formula = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

AB ==>

$= \sqrt{ {(2 - 0)}^{2} + {(0 - 2)}^{2} } \\ = \sqrt{4 + 4} \\ = \sqrt{8} \\ = 2 \sqrt{2} \: \: units$

BC ==>

$= \sqrt{ {( - 2 - 2)}^{2} + {(0 - 0)}^{2} } \\ = \sqrt{16} \\ = 4 \: \: units$

AC ==>

$= \sqrt{ {( - 2 - 0)}^{2} + {(0 - 2)}^{2} } \\ = \sqrt{4 + 4} \\ = \sqrt{8} \\ = 2 \sqrt{2} \: units$

AB = AC

Therefore, triangle ABC is ISOSCELES.

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