Question

plz plz help me to solve this

Answer 1

4/x-3/y=7----------------1
3/x+4/y=24--------------2
let 1/x be u and 1/y be v
4u+3v=7 ----------------3
3u+4v=24---------------4
from 3
u=(7-3v)4-------------5
substituting 5 in 4
3(7-3v)/4+4v=24
(21-9v)/4+4v=24
(21+7v)/4=24
21+7v=96
7v=75
v=75/7
u=(7-3*75)/4*7
=(7-225)28
u=218/28
x=7/75
y=28/218

Answer 2

4/x-3/y=7 ------->(1)
3/x + 4/y = 24 ------->(2)
Hey here is the solution
Let 1/x = a
1/y= b
then equation (1) and (2) become
4a - 3b = 7 -----> (3)
3a + 4b = 24 -------> (4)
multiplying 4 in equation (3) and 3 in equation (4) we get
16a - 12b = 28 ------>(5)
9a + 12b = 72 ------->(6)
now adding equation (5) and (6) we get
16a - 12b = 28
+ 9a + 12b = 72
----------------------------
25a = 100
a=100/25
a=4
putting value of a in equation (4) we get
3(4)+4b=24
12 + 4b = 24
4b = 24 - 12
4b = 12
b = 12/4
b = 3
now
1/x=a
=> 1/x = 4
=> x= 1/4
1/y = b
1/y=3
y = 1/3
HOPE IT HELPS YOU
ALL THE BEST FOR EXAM