Physics, asked by Veer1111, 1 year ago

plz plz plz ans this ques

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Answered by rameshafernandosrtzc
1
1) In a v-t graph the gradient shows the acceleration. (Used two coordinates)

∴ a from A-B = (25 - 5)/(3-1) = 10 ms^-2 [gradient = y axis/x axis]

2) Similarly,
   a from B-C = (10-25)/(5-3) = - 7.5 ms^-2 (Here a negative gradient means deceleration)

3) In a v-t graph the area shows the displacement,
    ∴ s = 1/2 (3x25)  [Area of the triangle ABE]
           = 37.5 m

4) Average velocity = Total displacement / Total time
                                = {1/2(2*15.5)} / 2
                                = 15.5 / 2
                                = 7.75 ms^-1
5) Area of the trapezium = 1/2(15.5 + 25) * 1
                                        =  20.25 m


Veer1111: can u plz do 4,5 part again
Veer1111: 4ans is -8.5m/s
Veer1111: 5ans is 21 m
Veer1111: can u do it plsssssss
rameshafernandosrtzc: Ok! Plz wait
rameshafernandosrtzc: Oh I'm Sry! Yeah, You have to take the y coordinate corresponding to point C as 17. Then for 4) Average velocity = (Final velocity + Initial velocity) / 2 = (-17 +0) / 2 = -8.5 ms^-1 And for 5) (17+25)/2 = 21m
Veer1111: thankuuu so much
rameshafernandosrtzc: Anytime!
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