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Step-by-step explanation:
CD=DE and angle CED is an angle in a semicircle so it is 90
let DCE=CDE=x (CE=CE isosceles triangle)
in triangle CED 2x+90=180
x=45
and tangent is perpendicular to the circle at that point
GCD=90
DCE+ECG=DCG
so GCE=90-x=45
also DCE=DCB+BCE
so BCE=45-15=30
thus GCE is 45 degrees
and BCE is 30 degrees
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