Math, asked by Anshimish0105, 1 year ago

plz plz plz answer this. ASAP

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Answered by sanjay270899
4
After calculation from the above image,

Area of shaded region = area of circle - an area of an equilateral triangle

Area of shaded region

 = \pi {(radius)}^{2} - \frac{ \sqrt{3} }{ 4 } {(side)}^{2}

(CM is the radius of the given circle)

 = \pi {( \frac{14}{ \sqrt{3} } )}^{2} - \frac{ \sqrt{3} }{ 4 } {(14)}^{2}

 = {14}^{2} (\frac{\pi}{3} - \frac{ \sqrt{3} }{4} )

 = {14}^{2} (\frac{4\pi - 3 \sqrt{3} }{12} ) \:

 = \frac{49}{3} ({4\pi - 3 \sqrt{3} } ) \:

 = \frac{7}{3} ({88 - 21 \sqrt{3} } ) \: c {m}^{2}

 = \frac{7}{3} ({51.626933} ) \: c {m}^{2}

 = 120.46 \: c {m}^{2}
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