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initial speed ,u=90km/h =90 x1000/3600 m/s
=25m/s
final speed ,v = 0m/s
uniform acceleration ,a= -0.5m/s^2
using equation of motion : v2= u2+2as
0=25^2 + 2x(-0.5)xs
s=distance =625m
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Explanation:
Initial velocity, u = 90 km/hr 90*5/18 = 25 m/sec
Final velocity, v= 0 ( as brakes are applied)
Acceleration, a = -0.5m/second square
From third equation of motion:
2as = v square-u square
2*(-0.5)s = 0 square - 25 square
-s = -625
minus minus will cancel each other
s = 625m
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