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i) angle BAC
angle sum property :-
let angle A be 'x'
90°+40°+x° = 180°
130°+x°=180°
x=180 - 130
x = 50°
ii) angle ACD
90/2 (because bisector divides the triangle equally)
= 45°
iii) angle BCD
angle sum property :-
angle CDB = 90° (given)
angle B = 40°
90°+40°+C= 180°
130° + C = 180°
C = 180° - 130°
C = 50°
HOPE IT HELPS MATE
•PLZ MARK MY ANSWER AS THE BRAINLIEST ONE•
angle sum property :-
let angle A be 'x'
90°+40°+x° = 180°
130°+x°=180°
x=180 - 130
x = 50°
ii) angle ACD
90/2 (because bisector divides the triangle equally)
= 45°
iii) angle BCD
angle sum property :-
angle CDB = 90° (given)
angle B = 40°
90°+40°+C= 180°
130° + C = 180°
C = 180° - 130°
C = 50°
HOPE IT HELPS MATE
•PLZ MARK MY ANSWER AS THE BRAINLIEST ONE•
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