plz plz plz help me
its a question of class 11 ch gravitation
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Answered by
1
Answer:
10 root 10 : 1
Step-by-step explanation:
Acc to keplers laws
T^2 is directly proportional to r^3
(T1/T2)^2=(r1/r2)^3
T1/T2=(10^11/10^10)^3/2
T1/T2=10 root 10 / 1
Hope it helps
Answered by
1
Step-by-step explanation:
we have ,
distance between two planets (r1 and r2) = 10^11 and 10^10 .
now , we find the ratio of time period of two panets .
r1 = 10^11
r2 =10^10m
then,
T1/T2 =(r1/r2)^3/2
now puttung the value of r1 and r2 ,
T1/T2 = (10^11 /10^10)^3/2
= 10^3/2
= 10√10 .
hence the ratio of time period of two planets is 10√10.
Thnks for asking question
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