Math, asked by jmtindian, 8 months ago

plz plz plz help me
its a question of class 11 ch gravitation ​

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Answers

Answered by bsrsyamala
1

Answer:

10 root 10 : 1

Step-by-step explanation:

Acc to keplers laws

T^2 is directly proportional to r^3

(T1/T2)^2=(r1/r2)^3

T1/T2=(10^11/10^10)^3/2

T1/T2=10 root 10 / 1

Hope it helps

Answered by yashgujjarji
1

Step-by-step explanation:

we have ,

distance between two planets (r1 and r2) = 10^11 and 10^10 .

now , we find the ratio of time period of two panets .

r1 = 10^11

r2 =10^10m

then,

T1/T2 =(r1/r2)^3/2

now puttung the value of r1 and r2 ,

T1/T2 = (10^11 /10^10)^3/2

= 10^3/2

= 10√10 .

hence the ratio of time period of two planets is 10√10.

Thnks for asking question

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