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On a foggy day, two car drivers spot each other, at when they were 80 meters apart. They aate travelling at 72 km/hr and 60mk/h respectively towards each other. Both pf them simultaneously apply breaks, which retarded both the cars at a rahe of 5m/s^2. Determine werther they avert the collision offer not.
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Answer:
s=80m
v1=72*5/18=20m/s
just like that
v2=50/3m/s
Explanation:
so velocity of V1 with respect
v2=20+50/3
=110/3m/s
a1=-5m/s square = a2
so retardation with respect of other =5+5=10m/s square
ritika1862005:
please mark it as brainlist
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