Question

plz plz plz plz solve this question​

Answer 1

First one

Equation 1 : 1/(3x+y) +1/(3x-y) =3/4

Equation 2: 1/(3x+y) - 1/(3x-y) = -1/4

adding both the equations,

2/(3x+y) = -1/4 + 3/4

2/(3x+y) = 1/2

4=3x+y--->equation 3

subtracting eq. 1 and 2

2/(3x-y) =3/4+1/4

2/(3x-y) = 1

3x-y= 2--->equation 4

Adding equation. 3and 4

6x= 6

so x=1

and substituting value of x in equation 4 you get y as 1