Question

subtract 5a²/2+3a³/2+a/3-6/5 from a³/3-3a²-5/2​

Answer 1

Answer:

5a²/2+3a³/2+a/3-6/5 from a³/3-3a²-5/2

a³/3-3a²-5/2

-( 3a³/2+ 5a²/2 +a/3-6/5) : -3a³/2 - 5a²/2 - a/3 + 6/5

a³/3-3a²-5/2 -3a³/2 - 5a²/2 - a/3 + 6/5

= a³/3 - 3a³/2 -3a²-5a²/2 - a/3 + 6/5 - 5/2

= a³×2/ 3×2 - 3a³×3/2×3 -3a² ×2/1×2 - 5a²/2 -a/3 + 6×2/5×2 - 5×5/2×5

= 2a³/6 - 9a³/6 - 6a²/2 - 5a²/2 - a/3 + 12/10 - 25/10

= - 7a³/6 - 11a²/2 - a/3 - 13/10