Question

plz plz plz solve it its really urgent​

Answer 1

Answer:

hello here is ur answer

Step-by-step explanation:

Given

angle CEB=52°

angleAED=angleBEC

So, angleAED= 52°

now in triangle AED

AE=DE

so angleADE=angleDAE

So 52°+x+x=180°

2x=128°

x=64°

so Angle ADB=64°

Now in triangle DEC

following above concept we get

angleACD=26°

Thanking You

Answer 2

Answer:

i)ADC=64°

ii)ACD=26°

Step-by-step explanation:

i)AED=CEB

opposite angles,

AED=52°

Using angle sum theorem,

AED+EAD+ADE=180

let ADE and EAD be x

x+x+52=180

2x=180-52

x=128/2

x=64

hence ADB=64°

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ii)BEC+CED=180

linear pair,

52+CED=180

CED=128.

Using angle sum theorem,

ACD+CED+EDC=180

let ACD and ECD be x

x+x+128=180

2x=180-128

x=52/2

x=26

hence ACD=26°

.............................

HOPE THIS HELPS YOU!!