plz plz solve Q 15.....its very important...
Attachments:
Answers
Answered by
1
In ∆ABC and ∆ABD,
Angle Cab = Angle Bad(A is the bisector)
AB = AB(COMMON)
AC= AD(GIVEN)
THUS, ∆ABC=∆ABD, BY C.P.C.T,
BC= BD(PROVED)
Angle Cab = Angle Bad(A is the bisector)
AB = AB(COMMON)
AC= AD(GIVEN)
THUS, ∆ABC=∆ABD, BY C.P.C.T,
BC= BD(PROVED)
Answered by
1
See thr attach file for ans
Attachments:
Similar questions