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6
86):-
work completed by 20 men=30 days,
then
work completed by 1 man=30×20=600 days,
hence
work completed by 25 men = 600/25=24 days,
87):-
x^1999 is divided by x²-1,
for remainder
x²-1=0,
x²=1,
x^(2×999+1),
(x²)^999 × x,
then it becomes,
(1²)^999 × x,
1 × x,
x
work completed by 20 men=30 days,
then
work completed by 1 man=30×20=600 days,
hence
work completed by 25 men = 600/25=24 days,
87):-
x^1999 is divided by x²-1,
for remainder
x²-1=0,
x²=1,
x^(2×999+1),
(x²)^999 × x,
then it becomes,
(1²)^999 × x,
1 × x,
x
ayushmauryayash:
the answer of 1 question is 24days
Answered by
2
Hey user
Here is your answer :-
__________________________________
Q.86
20 men takes 30 days to complete the work .
As the no. of men increases the no. of days decreases
Hence it is inverse proportion .
So product remains constant.
Let the no. of days be x
20 × 30 = 25 × x
600/25 = x
x = 24
So 25 men takes 24 days to complete the same work.
Q.87
In attachment
Here is your answer :-
__________________________________
Q.86
20 men takes 30 days to complete the work .
As the no. of men increases the no. of days decreases
Hence it is inverse proportion .
So product remains constant.
Let the no. of days be x
20 × 30 = 25 × x
600/25 = x
x = 24
So 25 men takes 24 days to complete the same work.
Q.87
In attachment
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