plz prove this trigonometry question.
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√2–sin10°+√3cos35°=sin55°+2cos65° -----------(1)
we know that , 65° = 35°+30°
cos(a+b)=cosacosb−sinasinb
Solving RHS by this :-
sin55°+2cos65° = =cos35+√3cos35−sin35 ---------(2)
putting (2) in (1) and solving we get ,
√2sin10=cos35−sin35 --------------(3)
so,
cos35−sin35 = cos35−sin35 (Proved)
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