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Answer:
x^3+y^3 = 91.
hope this answer is helps you.
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x + y = 7
y = 7 - x
Now x^2 + y^2 = x^2 + ( 7- x)^2
x^2 + 49+ x^2 - 14x
= 2x^2 - 14x + 49
According to the question =
2x^2 - 14x + 49 = 25
2x^2 - 14x = - 24
2x^2 - 14x + 24 = 0
x^2 - 7x + 12 = 0
x^ 2 - 4x - 3x + 12 = 0
x( x - 4) - 3(x - 4) = 0
( x - 4) ( x - 3) = 0
X - 4 = 0
x = 4
Or
x - 3 = 0
x = 3
take the value of x either 4 or 3, let's take 4
There it is given, x + y = 7
4+y = 7
y= 3
x^3 + y^3 = 4^3 + 3^3 = 64 + 27 = 91
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