Question

plz say fast.......​

Answer 1

$\huge\mathfrak\pink{Answer}$

Given:

a = 9x² -7xy+2y²

b = 3y²+2xy -x²

c = -5y²+5xy-8x²

To show that:

a+b+c = 0

Solution:

by putting values

(9x² -7xy +2y²)+(3y²+2xy -x²)+(-5y²+5xy-8x²)

= 9x² -7xy+2y²+3y²+2xy -x²+-5y²+5xy-8x²

= (9x²-x²-8x²)+(-7xy+2xy+5xy)+(2y²-5y²+3y²)

= (9x²-9x2)+(-7xy+7xy)+(5y²-5y²)

= 0

hence proved a+b+c = 0.

Extra information-

${\pink{\boxed{(a+b)^2 = a^2+b^2+2ab}}}$

${\pink{\boxed{(a-b)^2 = a^2+b^2-2ab}}}$

${\pink{\boxed{(a+b)(a-b) = a^2-b^2}}}$

${\pink{\boxed{(a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca)}}}$

${\pink{\boxed{(a+b)^3 = a^3+b^3+3ab(a+b)}}}$

Answer 2

Answer:

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