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3) you have to draw a line with two arrow marks both sides which represents a straight lineAB.
4) given that c is the middle point on the line AB so distance between AC and CB are equal.
so, AC=BC=7 and last AB=AC+CB=7+7=14
5) given that A, B and C are Collinear points then the line segment are AB, AC, BC.
6) here AC, OA, OC, OB, OD, AD, DC, CB, AB in first figure. AD, AB, AE, BD, BC, CD, BD.
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I need some points so I will answer your questions .
Sorry bro.
Please understand.
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