Question

plz send answer any one

Answer 1

angle ACR = 125 Degree
angle BCD = 25 Degree
y + 25 degree + 125 degree = 180 degree (linear pair)
y = 180 - 150
y = 30 degree

angle BAQ + angle A (external) = 180 degree (linear pair)
110 + angle A = 180 degree
angle A = 180 - 110
angle A = 70 degree

angle A (internal) = 70 degree (Verically Opposite Angle)

angle z + angle y + angle A(internal) = 180 degree (Sum of all angles of a triangle)
angle z + 30 + 70 = 180 degree
angle z = 180 - 100
angle z = 80 degree

angle z + angle D = 180 degree (linear pair)
80 + angle D = 180 degree
angle D = 180 - 80
angle D = 100 degree

angle x + 25 + 100 = 180 degree (Sum of all angles of a triangle)
angle x = 180 - 125
angle x = 55degree

HOPE IT HELPS YOU....

Answer 2

Your answer is X=55, y=30, z=80